30x^2+34x-8=0

Solution for 30x^2+34x-8=0 equation:

30x^2+34x-8=0

a = 30; b = 34; c = -8;
Δ = b2-4ac
Δ = 342-4·30·(-8)
Δ = 2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2116}=46$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-46}{2*30}=\frac{-80}{60}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+46}{2*30}=\frac{12}{60}
=1/5
$